从网上看到一个java题，没事练练，搞不定。
题目和我写的java代码如下：/*编写一个Java应用程序，利用RandomAccessFile类，把几个int型整数（1，2，3，4，5，6，7，8，9，10）写入到一个名字为tom.dat文件中，
然后按相反顺序读出这些数据并显示在屏幕上。（注意，一个int型数据占4个字节）
*/
import java.io.*;
public class ReadFile {
/**
* @param args
* @throws IOException
*/
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
File file = new File("D:/tom.dat");
try {
RandomAccessFile RandomAccess = new RandomAccessFile(file, "rw");
for (int i = 1; i <= 10; i++) {
try {
RandomAccess.writeInt(i);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
try {
RandomAccess.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
RandomAccessFile randomFile = new RandomAccessFile(file, "r");
/*
* for (int i = 1; i <= 10; i++) {
randomFile.seek(i);
int j = randomFile.readInt();
System.out.println(j);
} 从前往后读，正常，可以读取1,2,3,4,5,6,7,8,9,10，
但是从后往前读,结果为196608 768 3 3355 4432 131072 512 2 16777216 65536 256
* */
try {
for (int i = 10; i >= 1; i--) {
randomFile.seek(i);
int j = randomFile.readInt();
System.out.println(j);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
randomFile.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
这是运行结果
196608
768
3
33554432
131072
512
2
16777216
65536
256
哪位大侠帮忙搞定一下啊 --------------------编程问答--------------------
RandomAccessFile file = null;
try {
file = new RandomAccessFile("example.dat","rw");
for (int i = 1; i <= 10; i++) {
file.writeInt(i);
}
} catch (final IOException e) {
System.err.println(e.getMessage());
} finally {
try {
if (file != null) {
file.close();
}
} catch (final IOException e) {
System.err.println(e.getMessage());
}
}
try {
file = new RandomAccessFile("example.dat","r");
for (int i = 1; i <= 10; i++) {
System.out.println(file.readInt());
}
} catch (final IOException e) {
System.err.println(e.getMessage());
} finally {
try {
if (file != null) {
file.close();
}
} catch (final IOException e) {
System.err.println(e.getMessage());
}
}
try {
file = new RandomAccessFile("example.dat","r");
for (int i = 9; i >= 0; i--) {
file.seek(i*4L);
System.out.println(file.readInt());
}
} catch (final IOException e) {
System.err.println(e.getMessage());
} finally {
try {
if (file != null) {
file.close();
}
} catch (final IOException e) {
System.err.println(e.getMessage());
}
}
你没看过seek的文档。按字节移动定位。提示你int是4字节。 --------------------编程问答--------------------
+1
补充：Java , Java SE
