您好，请教一个问题，请问在php接收表单数据页面内怎么利用js获得复选框的value值插入到数据库内？

QQ:1274731799

补充：表单内有多个问题，每个问题下都有许多复选框选项

答案：<?php

/*
 * Created on 2011-6-21
 *
 * To change the template for this generated file go to
 * Window - Preferences - PHPeclipse - PHP - Code Templates
 */
include ("admin_head.php");
error_reporting(E_ALL & ~E_NOTICE & ~E_WARNING);
$url = $_SERVER["REQUEST_URI"];
$url = parse_url($url);
$url = $url[path];
$User_ID = $_GET[User_ID];
$User_Authr = $_GET[User_Authr];
include_once ("conn.php");
$db->getinfo("map_info_tb");
$num_all = $db->num_rows();
while ($row = $db->showinfo()) {
	$Map_ID[] = $row[0];
	$Map_Name[] = $row[1];
}
$db->getinfo1("user_map_list", "User_ID", "'$User_ID'");
$num_old = $db->num_rows();
while ($row = $db->showinfo()) {
	$selected[] = $row[1];
}
?>
<form id="form1" name="form1" method="post" action="user_info_edit.php?User_ID=<?=$User_ID?> & User_Authr=<?=$User_Authr?>">
  <p>
 <?

for ($i = 0; $i < $num_all; $i++) {
?>
    <label>
      <input type="checkbox" name="checkbox<?=$i?>" value="<?=$Map_ID[$i]?>" <?for($j=0;$j<$num_old;$j++){if($selected[$j]==$Map_ID[$i])echo "checked=\"checked\"";}?>/>
      <?=$Map_Name[$i]?></label>
    <br />
 <?

}
?>
  </p>
<input type="submit" name="submit" value="提交"><input type="reset" name="reset" value="重置">
</form>
<?

if (isset ($_POST['submit']) && $_POST['submit']) {
	for ($i = 0; $i < $num_all; $i++) {
		if (isset ($_POST["checkbox$i"])) {
			$new_selected[] = $_POST["checkbox$i"];
		}
	}
    include_once("conn.php");
    $db->delete("user_map_list","User_ID","'$User_ID'");
	$num_new = count($new_selected);
	for ($i = 0; $i < $num_new; $i++) {
				include_once ("conn.php");
				$db->insert("user_map_list", "User_ID,Map_ID", "'$User_ID','$new_selected[$i]'");
			}
			$url="user_info.php?User_ID=$User_ID & User_Authr=$User_Authr";
			echo "<script language=\"javascript\">location.href='$url';</script>";
		}


?>
希望对你有帮助！

其他：一定要用JS吗……php本身不是也能传值到数据库里面吗？？ 

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