一个Android框架下实现登录和Google检索的应用程序
1. 需求设计
在Android的数据库创建一个login表，包括密码和账户两个字段实现两个activity应用程序，其中一个，提供两个入力框，分别输入密码和账户，并且实现登录check
登录成功之后，跳转到第二个Activity，在其上实现一个入力框，根据输入的参数，到google上检索
2. 效果图
3. 主要代码
3.1 第一个Activity的代码public class Android1 extends Activity {
private Button mButton1;
private TextView mTextView1;
private TextView mTextView2;
private String user = new String();
private String password = new String();
private DBHelper dbHelper;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mTextView1 = (TextView) findViewById(R.id.EditText01);
mTextView2 = (TextView) findViewById(R.id.EditText02);
dbHelper = new DBHelper(this, "TestDB");
createTable();
}
public void onClick(View v) {
// TODO Auto-generated method stub
user = mTextView1.getText().toString();
password = mTextView2.getText().toString();
Boolean result = selectTable(user, password);
Log.d("Android1", "the result is " + result);
if (result == true) {
Intent intent = new Intent();
intent.setClass(Android1.this, Android2.class);
startActivity(intent);
}
}
public void createTable() {
SQLiteDatabase db = dbHelper.getWritableDatabase();
db
.execSQL("create table if not exists LOG (user varchar primary key,password varchar)");
}
public boolean selectTable(String user, String password) {
SQLiteDatabase db = dbHelper.getWritableDatabase();
try {
Cursor result = db.rawQuery(
"select * from LOG where user = ? AND password =?",
new String[] { user, password });
Log.d("Android1", "count is " + result.getCount());
if (result.getCount() != 0) {
result.close();
db.close();
return true;
} else {
result.close();
db.close();
return false;
}
} catch (SQLException ex) {
Log.d("Android1", "select table failure");
return false;
}
}
}
3.2 第二个Activity的代码
public class Android2 extends Activity {
private TextView mTextView1;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.search);
mTextView1 = (TextView) findViewById(R.id.EditTextSearch);
}
public void onClick(View v) {
String key = mTextView1.getText().toString();
&n
补充：移动开发 , Android ,
