createPopup 弹出窗口如何定位到屏幕右下角?(急)

实现功能:
   用createPopup创建弹出窗口,并把创建的弹出窗口在屏幕的右下方显示.
问题:
   当通过本地做的HTML测试的时候,可以实现上面的功能.但是把期布置在WEB服务器上的时候,发现期弹出窗口跟着浏览器显示,不能在屏幕的右下方显示.也把WEB站点设置为了可信站点,但是也没能实现.求解决办法?
补充问题:
   运行环境:IE8.0,WEB服务器为TOMCAT5.0,操作系统为XP系统.
事例代码如下:
<html>
<head>
</head>
<SCRIPT language="javascript" >
function popmsg(qr_whdanmsg,whdanmsg,mimamsg){
var oPopup = window.createPopup();
var popTop=50;

var winstr=" <table style=\"border: 1 solid  #FFA6CA\"  width=\"241\" height=\"172\" border=\"0\" cellpadding=\"0\" cellspacing=\"0\">";
    winstr+=" <tr>";
    winstr+=" <td height=\"25\">  </td>";
    winstr+=" </tr>";
    winstr+=" <tr>";
    winstr+=" <td height=\"25\" align=\"center\" valign=\"top\" style=\"font-size:12px; color: red; face: Tahoma ;\" >"+whdanmsg+" </td>";
    winstr+=" </tr>";
    winstr+=" <tr>";
    winstr+=" <td height=\"25\" align=\"center\" valign=\"top\" style=\"font-size:12px; color: red; face: Tahoma ;\" >"+qr_whdanmsg+" </td>";
    winstr+=" </tr>";
    winstr+=" <tr>";
    winstr+=" <td height=\"25\" align=\"center\" valign=\"top\" style=\"font-size:12px; color: red; face: Tahoma;\" >"+mimamsg+" </td>";
    winstr+=" </tr>";
    winstr+=" <tr>";
    winstr+=" <td>  </td>";
    winstr+=" </tr>";
    winstr+=" </table>";

oPopup.document.body.innerHTML = winstr;

popshow(oPopup,popTop);

}

var _st = window.setTimeout;

  window.setTimeout = function(fRef, mDelay) {

       if(typeof fRef == 'function'){

                   var argu = Array.prototype.slice.call(arguments,2);

                    var f = (function(){ fRef.apply(null, argu); });
       return _st(f, mDelay);
  }
return _st(fRef,mDelay);
}

function popshow(oPopup,popTop){

window.status=popTop;
if(popTop>1720){

popTop=50;

}else if(popTop>1520&&popTop <1720){
oPopup.show(screen.width-250,screen.height,241,1720-popTop);
}else if(popTop>1500&&popTop <1520){
oPopup.show(screen.width-250,screen.height+(popTop-1720),241,172);
}else if(popTop <180){
oPopup.show(screen.width-250,screen.height,241,popTop);
}else if(popTop <220){
oPopup.show(screen.width-250,screen.height-popTop,241,180);
}
popTop+=10;

var mytime=setTimeout(popshow,50,oPopup,popTop);

}

window.setInterval(popmsg("a","b","c"),5000);

</SCRIPT>

<body>
</body>
</html>

HTML 浏览器 --------------------编程问答--------------------

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补充：Java ,  Web 开发