前端js也能写算法

[html]
<!doctype html>
<html>
<head>
<title>html5 迷宫算法</title>
<style>
body{background-color:green;}
#map{marign:100px auto;width:330px;font-family:"微软雅黑";font-size:12px;}
#map:after{content:"";clear:both;}
#map > div{width:60px;line-height:60px;height:60px;margin:2px 0 0 2px;background-color:#ccc;float:left;text-align:center;color:white;font-weight:bold;}
#map > div.box8{background-color:green;}
#map > div.box5{background-color:red;}
#map > div.box1{background-color:#f93;}
#map > div.step{background-color:green;}
#map > div.null{background-color:white;}
</style>
</head>
<body>
<div id="map">
</div>
<script>
Array.prototype.clone=function(){
    return [].concat(this);
}
var game = function(element,options){
    options = options || {number:9};
    this.element = this.get(element);
    this.width = Math.pow(options.number,0.5);
    this.timer = 1000;
    this.crossrate = 0.9;//杂交率
    this.mutationrate = 0.1 //变异率
    this.veclen =400;//基因组的长度
    this.zero = null;
    this.count = 0;
    this.good = null;
    this.inerterval = null;
    this.finished = false;
    this.map = (function(){
                    // 随即生成1到100的打乱的数组，这个算法是跟JK学习的，也算是一种洗牌算法，感觉不错，谢谢JK
                    var i,
                        len = 9,
                        oldsource = [1,2,3,4,5,6,7,8,0];
                    var cpos = 8,tmp;
                    for(i = 0 ; i < 1000 ; i++){
                        var random = Math.floor(Math.random()*5);
                        if(random == 0){//上
                            if(cpos < 3){
                                continue;
                            }else{
                                tmp = oldsource[cpos];
                                oldsource[cpos] = oldsource[cpos-3];
                                oldsource[cpos-3] = tmp;
                                cpos = cpos -3;
                            }
                        }else if(random == 1){
                            if(cpos >=6){
                                continue;
                            }else{
                                tmp = oldsource[cpos];
                                oldsource[cpos] = oldsource[cpos+3];
                                oldsource[cpos+3] = tmp;
                                cpos = cpos +3;
                            }
                        }else if(random == 2){
                            if(cpos % 3 ==0){
                                continue;
                            }else{
                                tmp = oldsource[cpos];
                            &n

补充：web前端 , JavaScript ,