当前位置:数据库 > SYBASE >>

MSSQL转Sybase问题

实现这样 nd deptid xmid money 2008 001000000 j001 220.00 2008 001060000 g004 65.00 2008 001060000 j006 45.00 2008 001060000 j001 6.00//这个加下面的 2008 001060000 j00101 34.00 如果xmid的前四位、deptid、nd相同的则sum(money) 上表实现这样的 nd deptid xmid money 2008 001000000 j001 220.00 2008 001060000 g004 65.00 2008 001060000 j006 45.00 2008 001060000 j001 40.00//变成这个 2008 001060000 j00101 34.00 MSSQL里面通过 declare @tb table( nd varchar(4), deptid varchar(9), xmid varchar(10), money decimal(18,2) ) insert into @tb select '2008', '001000000', 'j001', 220.00 insert into @tb select '2008', '001060000', 'g004', 65.00 insert into @tb select '2008', '001060000', 'j006', 45.00 insert into @tb select '2008', '001060000', 'j001', 6.00 insert into @tb select '2008', '001060000', 'j00101', 34.00 select a.nd, a.deptid,a.xmid, ( select sum(b.money) from @tb b where b.nd = a.nd and b.deptid = a.deptid and b.xmid like a.xmid + '%' ) as money from ( select nd, deptid,xmid,sum(money) as money from @tb group by nd, deptid, xmid ) a /*结果 nd deptid xmid money ---- --------- ---------- ---------------------------------------- 2008 001000000 j001 220.00 2008 001060000 g004 65.00 2008 001060000 j001 40.00 2008 001060000 j00101 34.00 2008 001060000 j006 45.00 */ 请问在SBYASE里面怎么改呢? 谢谢 ------------------------------------------------ CREATE VIEW dbo.viem_yszcmx ( nd, deptid, xmid, ysmoney ) AS select a.nd, a.deptid, a.xmid, ( select sum(b.money) from yszcmx , b where b.nd = a.nd and b.deptid = a.deptid and b.xmid like a.xmid + '%' ) as money from ( select yszcmx.nd, yszcmx.deptid, yszcmx.xmid, sum(money) as money from yszcmx WHERE ( yszcmx.shzt <> '2' ) AND ( yszcmx.xzzt <> '2' ) group by yszcmx.nd, yszcmx.deptid, yszcmx.xmid ) a 求高人改成sybase11能用的视图代码!!! 谢谢了
补充:视图转换问题
答案:SELECT t3.nd,t3.deptid,mid(t3.xmid,1,4) as xmid ,sum(t3.money) as Xmoney 
FROM t3 group by t3.nd,t3.deptid,mid(t3.xmid,1,4)

标准语句在哪儿都可以执行

上一个:关于MSSQL中触发器的问题
下一个:怎样把MSSQL数据库还原到虚拟主机上啊

Oracle
MySQL
Access
SQLServer
DB2
Excel
SQLite
SYBASE
Postgres
如果你遇到数据库难题:
请访问www.zzzyk.com 试试
CopyRight © 2012 站长网 编程知识问答 www.zzzyk.com All Rights Reserved
部份技术文章来自网络,