高人请进，有要事相商
我要在VB.NET中写一段指令，实现对数组（由数据库传过来，可假设数组为S，即所谓的一系列x,y坐标）的曲线生成，请高人帮忙写个代码，感谢（我感觉思路是这样的：假定一个数组S,用Line指令画连接数组中两点的直线，做个循环，生成曲线）
以下内容可供参考：
Dim x0, y0, h, w
Dim I as integer
x0 = Shape1.Left
y0 = Shape1.Top + Shape1.Height
h = Shape1.Height / 1
w = Shape1.Width / 300
Picture1.ForeColor = QBColor(1)
Picture1.Cls
Y1 = Shape1.Height
For I=0 to 600
Picture1.Line (x0 + i * w, y0 - dqsj(i) * h)-(x0 + (i + 1) * w,y0 - dqsj(i + 1, Q) * h )
Next
//说明：其中，dqsj是记录10分钟内实时采集速度值的数组。
--------------------编程问答-------------------- --------------------编程问答-------------------- 你的思路可以，把两两相邻的点用line连接起来就形成曲线了
//这是一段画曲线以及x坐标和y坐标的代码，你可以参考一下，有点多
private void DrawPowerData(Graphics g)
{
Pen pen = null;
SolidBrush brush = new SolidBrush(Color.Black);
float leftMargin = 20;
float topMargin = 20;
float xOffSet = this.Width / 2;
float yOffSet = this.Height / 2 + 10;
float OneCardWidth = this.Width / 2;
float OneCardHeight = this.Height / 2 - 10;
int YMax = ((int)Math.Ceiling((double)(m_powerData.maxY / 10f))) * 10;
int YMin = ((int)Math.Floor((double)(m_powerData.minY / 10f))) * 10;
int XMax = (int)Math.Ceiling((double)m_powerData.maxX);
int XMin = ((int)Math.Floor((double)(m_powerData.minX / 10f))) * 10;
if (XMax == XMin || YMax == YMin)
return;
float XUnit = (OneCardWidth - leftMargin * 1.5f) / ((float)(XMax - XMin));
float YUnit = (OneCardHeight - topMargin * 2) / ((float)(YMax - YMin));
pen = new Pen(Color.Black);
//X轴
g.DrawLine(pen, leftMargin + xOffSet , (YMax - YMin) * YUnit + topMargin + yOffSet, XMax * XUnit + leftMargin + xOffSet, (YMax - YMin) * YUnit + topMargin + yOffSet);
for (int i = 0; i <= XMax; i++)
{
SizeF s = g.MeasureString(i.ToString(), this.Font);
g.DrawString(i.ToString(), this.Font, brush, i * XUnit + leftMargin + xOffSet - s.Width / 2, (YMax - YMin) * YUnit + topMargin + yOffSet + 5);
if (i == 1)
{
pen.DashStyle = DashStyle.Dash;
}
g.DrawLine(pen, i * XUnit + leftMargin + xOffSet, (YMax - YMin) * YUnit + topMargin + yOffSet, i * XUnit + leftMargin + xOffSet, topMargin + yOffSet);
}
//画y轴
for (int i = YMin; i <= YMax; i = i + 10)
{
SizeF s = g.MeasureString(i.ToString(), this.Font);
g.DrawString(i.ToString(), this.Font, brush, leftMargin + xOffSet - s.Width, (YMax - i) * YUnit + topMargin + yOffSet - s.Height / 2);
g.DrawLine(pen, leftMargin + xOffSet, (YMax - i) * YUnit + topMargin + yOffSet, XMax * XUnit + leftMargin + xOffSet, (YMax - i) * YUnit + topMargin + yOffSet);
}
//写标题
brush.Color = Color.Red;
SizeF st = g.MeasureString(m_powerData.GetTitle(), this.Font);
g.DrawString(m_powerData.GetTitle(), this.Font, brush, (OneCardWidth - st.Width) / 2 + xOffSet, yOffSet + 3);
//画曲线
pen = new Pen(Color.Red);
float x1 = (m_powerData.mPos[m_powerData.mPos.Length - 1] * XUnit) + leftMargin + xOffSet;
float y1 = (m_powerData.maxY - m_powerData.mLoad[m_powerData.mPos.Length - 1]) * YUnit + topMargin + yOffSet;
for (int i = 0; i < m_powerData.mPos.Length; i++)
{
float x2 = x1;
x1 = (m_powerData.mPos[i] * XUnit) + leftMargin + xOffSet;
float y2 = y1;
y1 = (m_powerData.maxY - m_powerData.mLoad[i]) * YUnit + topMargin + yOffSet;
g.DrawLine(pen, x1, y1, x2, y2);
}
brush.Dispose();
brush = null;
}
补充：.NET技术 , VB.NET
